3j^2+18j-48=0

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Solution for 3j^2+18j-48=0 equation:


Simplifying
3j2 + 18j + -48 = 0

Reorder the terms:
-48 + 18j + 3j2 = 0

Solving
-48 + 18j + 3j2 = 0

Solving for variable 'j'.

Factor out the Greatest Common Factor (GCF), '3'.
3(-16 + 6j + j2) = 0

Factor a trinomial.
3((-8 + -1j)(2 + -1j)) = 0

Ignore the factor 3.

Subproblem 1

Set the factor '(-8 + -1j)' equal to zero and attempt to solve: Simplifying -8 + -1j = 0 Solving -8 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1j = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1j = 0 + 8 -1j = 0 + 8 Combine like terms: 0 + 8 = 8 -1j = 8 Divide each side by '-1'. j = -8 Simplifying j = -8

Subproblem 2

Set the factor '(2 + -1j)' equal to zero and attempt to solve: Simplifying 2 + -1j = 0 Solving 2 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1j = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1j = 0 + -2 -1j = 0 + -2 Combine like terms: 0 + -2 = -2 -1j = -2 Divide each side by '-1'. j = 2 Simplifying j = 2

Solution

j = {-8, 2}

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